A study looked at n=238 adolescents, all free of severe illness.23 Subjects wore a wrist actigraph, which allowed the researchers to estimate sleep patterns. Those subjects classified as having low sleep efficiency had an average systolic blood pressure that was 5.8 millimeters of mercury (mm Hg) higher than that of other adolescents. The standard deviation of this difference is 1.4 mm Hg. Based on these results, test whether this difference is significant at the 0.01 level.

Answer:Step-by-step explanation:Since n < 30, we will find the t-score and compare that to the t-score of a significance level of 1%.    Since they are asking if the difference is significant, we will have a two tailed test, with degree of freedom being 22, so our critical values aret < -2.704 and t > 2.704Our t-value for this situation ist = ([µ + 5.8] - µ)/(1.4/√23)It's µ + 5.8 because the problem told us that their levels are 5.8 mm higher than the average, so it's the average, plus 5.8Simplify the equation...t = 5.8/(1.4/√23)t = 19.86819.868 > 2.704, the evidence supports that there is significant difference between the sample and the population